function

GNU Linux/Bash: A function that splits a word in half

 in Bash / GNU/Linux  tagged bash / fedora / function / GNU/Linux / howtos / line / split / string / text / ubuntu by

The following function takes one argument – a text file.
The text file should contain one word on each line.
The function reads the text file (argument) line by line.
Then it checks if the line has one word; if this is true, it splits the word in half.
Finally, it prints the two new words with a space between them.

#!/bin/bash

splitWordsInHalf () {
  # This function takes one argument - a text file.
  # The text file contains one word on each line.
  # It reads the text file (argument) line by line.
  # Then it checks if the line contains one word, if this is true, it splits the word in half.
  # Finally, it prints the two new words with a space between them
  while read line
  do
    words=( $line )
    if [ ${#words[@]} == 1 ]
    then
      echo ${line:0:${#line}/2} ${line:${#line}/2}
    fi
  done < $1
}

splitWordsInHalf input.txt

Example

Using the following input file:

banana
apple
ball
car
door

We will get the following output when we execute splitWordsInHalf input.txt:

ban ana
ap ple
ba ll
c ar
do or

Notes

The following parts of the code are in charge of looping on the data of the incoming file. The parameter (the input file) given to the function is translated into the variable $1. The while loop gets one line of text on each iteration and assigns the text to the variable that is named line. You could have chosen any other name that suits you instead of the word line.

splitWordsInHalf () {
  while read line
  do
    ...
  done < $1
}

The next part of the code (words=( $line )) converts the string value that is contained in the line variable into an array of words, and it assigns that array to the variable named words. Then, it counts the number of elements in the array (the number of words in the line) using the following ${#words[@]} and it checks that there is only one item.

words=( $line )
if [ ${#words[@]} == 1 ]
then
  ...
fi

The following line will print two strings. The first string is a sub-string of variable line that is composed by the first half of the value. The second sub-string is the second half of the value contained in the variable named line.

echo ${line:0:${#line}/2} ${line:${#line}/2}

The ${#line} will return the length of the string contained in the variable.

The structure ${VARIABLE:START:END} defines the slice of the string that we want returned.

Bash Function to print out the files and the lines that contain a needle

 in Bash  tagged bash / color / find / function by

The following code will create a function in bash that accepts two parameters (1: the place to search in, 2: the value to search for).

You can place it in your ~/.bashrc file to have it available whenever you open a bash shell.

#1. Copy/paste the below lines in your .bashrc

#takes 2 parameters (1: the haystack to search in, 2: the needle)
# Will print out the files and the lines that contain the needle
xfind(){
  FIND_VAR="$2";
  STACK="$1";
  if [ -f "$STACK" ] || [ -d "$STACK" ]; then
    find "$STACK" \
      -exec grep --color "$FIND_VAR" -sl '{}' \; \
      -exec grep "$FIND_VAR" -s '{}' \;
  else
    echo "ERROR: No file or folder with the name '$STACK' exist";
  fi
}
#2. Run source ~/.bashrc -- to reload

Usage examples:

xfind . "bar";
xfind /etc/ "conf";