Bash get script file name and location 1
The following code will populate the variables SCRIPT_NAME
and SCRIPT_DIR
with the name of the script currently being execute and the location this script is in:
1 2 | SCRIPT_NAME=$( basename $( test -L "$0" && readlink "$0" || echo "$0" )); SCRIPT_DIR=$( cd $( dirname "$0" ) && pwd ); |
Notes for SCRIPT_NAME
:
$0
expands to the name of the shell or shell scripttest -L "$0"
checks that input is a file that exists and is a symbolic link&& readlink "$0"
will be executed if the above statement is true and it will print the resolved symbolic link|| echo "$0"
will be executed if the test for symbolic link fails- finally,
basename
will strip directory and suffix from whatever is returned from the above statements
Notes for SCRIPT_DIR
:
- Will not resolve the correct folder if the last component of the path is a symbolic link (symlink). It will return the location of the symlink instead of the location of the file the symlink is pointing to
cd
will return0
if itsuccessfully navigates
to a directory or1
when itfails to navigate
to the directorycd "$( dirname "$0" )"
will usedirname
to strip the last component from the expanded name and try to navigate to that location- if the above
cd
fails, we get the current location using&& pwd
.pwd
will print name of current/working directory
In case you have a problem with $0
, it is overwritten or the above function is called by a child script in another folder you can replace $0
with ${BASH_SOURCE[0]}
.
1 2 | SCRIPT_NAME=$( basename $( test -L "${BASH_SOURCE[0]}" && readlink "${BASH_SOURCE[0]}" || echo "${BASH_SOURCE[0]}" )); SCRIPT_DIR=$( cd $( dirname "${BASH_SOURCE[0]}" ) && pwd ); |