C/C++: Change position of bytes 1 and 2 with bytes 3 and 4 in a 32bit unsigned integer

 στο C / C++  επισημασμένο με ετικέτα byte mask / byte operations / byte shift / C++ Από

The following function will produce a new 32bit value where bytes 1 and 2 were moved in place of bytes 3 and 4 and vice versa.

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#include <stdio.h>
#include <stdlib.h>
 
const unsigned int move_bytes_1_2_after_4 (const unsigned int input) {
  //We get the two leftmost bytes and move them to the positions of the two rightmost bytes.
  const unsigned int first_two_bytes = (input >> 16) & 0x0000FFFF;
  //We get the two rightmost bytes and move them to the positions of the two leftmost bytes.
  const unsigned int last_two_bytes = (input << 16) & 0xFFFF0000;
  //We combine the two temporary values together to produce the new 32bit value where bytes 1 and 2 were moved in place of bytes 3 and 4 and vice versa.
  return (first_two_bytes | last_two_bytes);
}
 
int main(void) {
  const unsigned int value = 0xABCD0123;
  printf ("Original: 0x%08x\n", value);
  const unsigned int modified = move_bytes_1_2_after_4(value);
  printf ("Modified: 0x%08x\n", modified);
  return EXIT_SUCCESS;
}

Executing the above code will produce the following output:

Original: 0xabcd0123
Modified: 0x0123abcd

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